(李浩光)
School of Mathematics and Statistics, South-Central Minzu University, Wuhan 430074, China;Key Laboratory of Mathematical Modelling and High Performance Computing of Air Vehicles,MIIT, Nanjing 210016, China
E-mail: lihaoguang@scuec.edu.cn
Chaojiang XU (徐超江)
School of Mathematics and Key Laboratory of Mathematical MIIT,Nanjing University of Aeronautics and Astronautics, Nanjing 210016, China
E-mail: xuchaojiang@nuaa.edu.cn
Abstract In this work,we study the linearized Landau equation with soft potentials and show that the smooth solution to the Cauchy problem with initial datum in L2(R3) enjoys an analytic regularization effect,and that the evolution of the analytic radius is the same as the heat equations.
Key words linear Landau equation;analytic smoothing effect;soft potential
In this work,we study the Cauchy problem of the spatially homogeneous Landau equation
whereF=F(t,v)≥0 is the density distribution function depending on the velocity variablesv ∈R3and the timet ≥0.The Landau bilinear collision operator is given by
One says that these are hard potentials ifγ>0,Maxwellian molecules ifγ=0,soft potentials ifγ ∈]-3,0[ and Coulombian potentials ifγ=-3.We shall study the linearization of the Landau equation (1.1) near the absolute Maxwellian distribution
Considering the fluctuation of the density distribution function
sinceQ(μ,μ)=0,the Cauchy problem (1.1) is reduced to the Cauchy problem
In this work,we study Cauchy problem of the linear Landau equation
Using reference [7],we show that the diffusion partLis written as
withA(v)=()1≤i,j≤3being a symmetric matrix where
For the hard potential case,the existence and uniqueness of the solution to the Cauchy problem for the spatially homogeneous Landau equation was already treated in [6,14]under a rather weak assumption on the initial datum.Moreover,the authors of these works proved the smoothness of the solution inC∞(]0,+∞[;S(R3)).In[2],Chen-Li-Xu improved this smoothing property and proved that the solution is in fact analytic for anyt>0 (see [3,4]for the Gevrey regularity).
For the Maxwellian molecules case,in[8],Lerner,Morimoto,Pravda-Starov and Xu studied the spatially homogeneous non-cutoffBoltzmann equation and the Landau equation in a closeto-equilibrium framework and showed that the solution enjoys the Gelfand-Shilov smoothing effect (see also [10,13]and [9]).This implies that the nonlinear spatial homogeneous Landau equation has the same smoothing effect properties as the classic heat equation or the harmonic oscillators heat equation.In addition,starting from anyL2initial datum att=0,the solution of the Cauchy problem is spatial analytic for anyt>0 and the analytic radius is.In the non-Maxwellian case,we cannot use the Fourier transformation and the spectral decomposition as in[8–10,13].Recently,Li and Xu in[11]proved the analytic smoothing effect of the solution to the nonlinear Landau equation with hard potentials and the Maxwellian molecules case;that is,γ ≥0.Concerning the soft potential and the Coulombic interaction,Guo [7]constructed global in time classical solutions near the Maxiwellians for any small initial datum belonging toHN,N ≥8.
In this work,we study the Cauchy problem of the linearized Landau equation with soft potentials-3<γ<0.We show that the smooth solution enjoys an analytic smoothing effect for a short time.The main theorem is stated below.
Theorem 1.1For soft potentials-3<γ<0 and for anyT>0,with the initial datumf0∈L2(R3),the Cauchy problem (1.3) admits a unique weak solution
Moreover,for anyα ∈N3and=min{t,1},there exists a positive constantCwhich depends only on‖f0‖L2(R3)andT,and we have that
Remark 1.2(i) Equivalently,for soft potentials and for anym ∈N,we have that
For the multi-indices,we use the notation from the binomial expansion:
(ii) We do not consider the Coulombic interaction in Theorem 1.1 because the inequality(2.4)only holds true forγ>-3.In fact,we think that the Coulombic case has similar estimate as Theorem 1.1,but the proofs are different.
The rest of the paper is arranged as follows: we prove the ultra-analyticity for the coefficient of the Landau operator in Section 2.In Section 3,we estimate the commutators and prove the coercivity property of the linear Landau operator.In Section 4,we study the Cauchy problem for the linear Landau equation,and show the existence and uniqueness properties of the weak solution.The analytic smoothing effect of the weak solution for the linear Landau equation with soft potentials will be proven in Section 5.In the Appendix,we introduce the Hermite operator and related results.
Forγ ∈R,denote that
where we use the notations〈v〉=(1+|v|2)1/2.
In addition,for the matrixAdefined in (1.4),we denote that
and the weighted norm,forθ ∈R,is
From formula (21) of Corollary 1 in [7],for anyθ ∈R,there existsC1>0 such that
where,for any vector-valued functionG(v)=(G1,G2,G3),we define the projection to the vectorv=(v1,v2,v3) as
Noticing that?f=Pv?f+(I-Pv)?f,we have that
we can also refer to [5]and the references thereins.We remark that the weights forfand?fare different in the definition of.
First,for anyγ>-3 andδ>0,we have that
This implies that
In the following,we prove that the coefficients of the linear Landau operator are ultraanalytic:
Lemma 2.1For anyβ ∈N3with|β|≥1 whereis as was defined in (1.4) with-3<γ<0,we have that,
Moreover,for anyβ ∈N3,
ProofForβ ∈N3with|β|≥1,without loss of generality,we set that
Direct calculation shows that,for any 1≤i ≤3,
For more details regarding the operatorsA±,i,we refer to the Appendix.By using the fact that
it follows from Cauchy-Schwartz’s inequality and (2.4) that
where we use the fact that
where{Ψα}α∈N3is the orthonormal basis inL2(R3).H?lder’s inequality and Poincaré’s inequality imply that
and along with the equalities (A.1) and (A.2),this shows that,
For the estimate of the remaining inequalities (2.7),an integration by parts inside the convolution and (2.8) show that
by using the fact that
From a calculation similar to that above,it follows that
For|β|≥1,the same estimate holds true for the last term,such that
This ends the proof of Lemma 2.1.
In order to prove the coercivity of the linear Landau operator,we need one more estimate to control the weighted.
Lemma 2.2Forf,g ∈S(R3),and for anyβ ∈N3andθ ∈R,we have that
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ProofIn fact,we have the inner product
We decompose the integration region [v,w]∈R3×R3into three parts:
For the first part,{|v|≤1},by Lemma 2.1 and (2.5),we have that
For the second part,{2|w|≥|v|,|v|≥1},we have that
Similarly to the proof of Lemma 2.1,one can verify that
We finally consider the third part,{2|w|≤|v|,|v|≥1}.Expandingaij(v-w) to get that
along with the fact that
we immediately have that
Since 2|w|≤|v|,|v|≥1,0
It follows from the inequality (2.9) and the norm equality (2.2) that
This is the inequality (2.10).This ends the proof of Lemma 2.2.
Proposition 3.1Letf ∈S(R3),and letLbe defined as in (1.3).For anyα ∈N3andθ ∈R,there exists a positive constantC0>0 which is independent ofαandθsuch that
Remark 3.2We have that
1.forα=0,θ=0,
2.for-3<γ<0,and anyN ∈N,0<δ<1,there existsCNsuch that
3.for|α|≥1,
whereαj0=max{α1,α2,α3}.
ProofRecalling the formulaLfin (1.3),for the smooth functionf,and integrating by parts,we have that
Then,using (2.1),we have that
Since,for any fixediorj,
where we use the result that
Similarly,one has that
Using the Leibniz formula,
and it follows that
Thus the proof of Proposition 3.1 is reduced to the estimations of terms R0(f) and R1(f),which we give by the following two lemmas:
Lemma 3.3We have,forα ∈N3that
ProofBy using (2.4),we get that
Then (2.3) implies that
For the term R01,we use that
It follows that
This gives the estimate of R0(f).
Lemma 3.4We have,forα ∈N3,|α|≥1 that
ProofNow we estimate R1.For the term R11(f),by using the inequality (2.10) in Lemma 2.2 directly,we obtain that
For the two terms,R13(f) and R14(f),we can deduce from the inequality (2.7) in Lemma 2.1 and (2.3) that
For the term R12(f),for|β|≥1,it follows from (2.6) in Lemma 2.1 that
Then we have that
We then conclude that
Substituting the estimates of R0(f),R1(f)into the decomposition(3.4)completes the proof of Proposition 3.1.
Proposition 4.1For-3<γ<0,T>0,f0∈L2(R3),the Cauchy problem (1.3) admits a unique weak solution
satisfying that
whereC0is as was defined in Proposition 3.1.
ProofThe existence of the weak solution is similar to that in [1,7,12].We consider the operator
For any? ∈C∞([0,T];S(R3)) with?(T)=0,it follows from (3.1) that
Sinceγ<0,we have that
This implies that
Then one can verify that
In what follows,we set the vector subspace as
Sincef0∈L2(R3),we define the linear functional as
where? ∈C∞([0,T],S(R3))with?(T)=0.From(4.1),the operatorP?is injective.Therefore the linear functionalGis well-defined,and moreover,we obtain that
This shows thatGis a continuous linear form on (U,‖·‖L1([0,T],L2(R3))).By using the Hahn-Banach theorem,Gcan be extended as a continuous linear form onL1([0,T];L2(R3)) with a norm smaller than 2e2C0T‖f0‖L2(R3).It follows from the Riesz representation theorem that there exists a uniquef ∈L∞([0,T];L2(R3)) satisfying that
Therefore,f ∈L∞([0,T];L2(R3)) is a weak solution of the Cauchy problem (1.3).Let∈L∞([0,T];L2(R3)) be another weak solution of the Cauchy problem (1.3) satisfying that
Settingw(t)=f(t)-(t),we have that,for all? ∈C∞0((0,T),S(R3)),
This shows thatw(t)=0 inL∞([0,T];L2(R3)).The proof of Proposition 4.1 is complete.
Remark 4.2If we use (3.2) in place of (3.1),we can prove that,for-3<γ<0,N ∈N,T>0,f0∈HN(R3),and Cauchy problem (1.3) admits a unique solution such that,for any 0≤δ<1,
Suppose now thatf0∈L2(R3),and letf?be the solution of the linear Landau equation with the initial datumη??f0∈H∞(R3) whereη?is a mollifier function;that is,
We remark that
Using Remark 4.2,we have thatf?is a smooth solution for 0<1.
Now we want to prove the estimate
withConly depending on‖f0‖L2(R3),so that by compactness of sequence{f?}and the uniqueness of the solution of the Cauchy problem (1.3),we get that
Letf?be the smooth solution of Cauchy problem (5.1) with 0<1.Then,similarly to the estimate of R0in Proposition 3.1 withθ=0,we have that
This implies that (sinceγ<0)
By using Gr?nwall’s inequality,for anyT>0 and 0 Letting|α|=1,it follows from Proposition 3.1 withθ=γthat By using the inequality (2.3),one can verify that,for any 0 Substituting into the estimate (5.4),we have that Integrating on [0,t]and using (5.3),one can verify that,for|α|=1, We remark that,here,the constantCdepends only on‖f0‖L2(R3)andT. Proposition 5.1For anym ∈N andα ∈N3,|α|=m,we have,for 0 whereConly depends on‖f0‖L2,and in particular,is independent onαand?. This proposition implies Theorem 1.1.To simplify the notation,we omit the supreme index?off?. ProofIn fact,we have proven that the assumption(5.6)holds true form=0,1,by(5.3)and (5.5). Now assume that the assumption (5.6) holds true for|α|≤m-1.This means,for any|α|≤m-1,for 0 We intend to prove the validity of (5.6) form.First, Lettingθ=in Proposition 3.1,it follows that It follows from the inequality (2.3) again that wherek0is chosen withαk0=max{α1,α2,α3},so that,by the induction assumption (5.7),for|α-ek0|=m-1, We get then that For the term B2(f),using the fact,for anyβ ≤α,γ<0,that and by using the induction assumption (5.7) for|α-β|≤m-1,for 0 We then get,for 0 For the term B3(f),by using the induction assumption(5.7)for|α-β|≤m-2,|α-ek0|=m-1, and we get then that Finally,for the term B4(f),by using the induction assumption (5.7) for|α-ek0|=m-1, We then get,for 0 Take the constantCsatisfying (5.5),and where the constants are defined by (5.11),(5.13) and (5.15),so that it depends only on‖f0‖L2andT.Combining (5.8),(5.9),(5.10),(5.12) and (5.14) ends the proof of Proposition 5.1. Conflict of InterestChaojiang Xu is an editorial board member for Acta Mathematica Scientia and was not involved in the editorial review or the decision to publish this article.All authors declare that there are no competing interests. Appendix The standard Hermite functions (?n)n∈Nare defined,forv ∈R,as wherea+is the creation operator The family (?n)n∈Nis an orthonormal basis ofL2(R) and we set,forn ≥0,α=(α1,α2,α3)∈N3,x ∈R,v ∈R3,that with|α|=α1+α2+α3.The family (Ψα)α∈N3is an orthonormal basis ofL2(R3) composed by the eigenfunctions of the 3-dimensional harmonic oscillator where Pkstands for the orthogonal projection In particular, whereμ(v) is the Maxwellian distribution.Setting we have that where (e1,e2,e3) stands for the canonical basis of R3.For more details regarding the Hermite functions,we refer to [13]and the references therein. Acta Mathematica Scientia(English Series)2023年6期